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Mumz [18]
4 years ago
8

Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem. A cube-shaped bin has

an edge length of 34 yard. What is the volume of the container?
Mathematics
1 answer:
Mrrafil [7]4 years ago
5 0
To find the volume of the container, you will substitute/put the edge length of 34 yards in place of s in the volume formula that is given. Thr formula would then be V = 34^3. This means 34 x 34 x 34. The answer would be V = 39304 cubic yards. This is a very large container!!
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Can you please show work if you can. Thank you
klemol [59]
17-34(304)$-5 this is what I put
7 0
3 years ago
Write the equation in standard form for the circle passing through ( - 2,0) centered at the origin.
Aleks04 [339]
X^2 + Y^2 = 4 This centers at origin, since h and k values are zero ( therefore nonexistent) and the radius is 2 so it goes through (-2,0)
5 0
3 years ago
The area of a soccer field at 7700 yd.². The width of the field is 70 yards. What is the perimeter of the field?
mario62 [17]
Since you know the area and the width, you can divide the area by the width to find the length. This gives you a length of 110 yards. To find the perimeter of the soccer field, you would add all the side lengths together. Since the width is 70, you would add 70 + 70, along with the length, 110 + 110. This gives you a perimeter of 360.
3 0
3 years ago
a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1
Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

\text {volume of cylinder }=\pi r^{2} h

Where "r" is the radius of cylinder

"h" is the height of cylinder and \pi is constant has value 3.14

Substituting the values in formula, we get

\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}

Taking square root on both sides,

r = \sqrt{4}\\\\r = 2

Thus the radius of the container is 2 centimeter

4 0
3 years ago
The figure shows a person estimating the height of a tree by looking at the
FrozenT [24]

Answer:

The proportion that can be used to estimate the height of the tree is option;

A. \dfrac{h}{12} = \dfrac{6}{5}

Step-by-step explanation:

The given parameters in the question are;

The medium through which the person looks at the top of the tree = A mirror

The angle formed by the person and the tree with the ground = Right angles = 90°

The distance of the person from the mirror, d₁ = 5 ft.

The height of the person, h₁ = 6 ft.

The distance of the tree from the mirror, d₂ = 12 ft.

The angle formed by the incident light from the tree on the mirror, θ₁ = The angle of the reflected light from the mirror to the person, θ₂

Let 'A', 'B', 'M', 'T', and 'R' represent the location of the point at the top of the person's head, the location of the point at the person's feet, the location of the mirror, the location of the top of the tree and the location of the root collar of the tree, we have;

TR in ΔMRT = The height of the tree = h, and right triangles ΔABM and ΔMRT are similar

The corresponding legs are;

The height of the person and the height of the tree, which are AB = 6 ft. and TR = h, respectively

The distances of the person and the tree from the mirror, which are BM = 5 ft. and MR = 12 ft. respectively

∴ The angle formed by the incident light from the tree on the mirror, θ₁ = ∠TMR

The angle of the reflected light from the mirror to the person, θ₂ = ∠AMB

Given that θ₁ = θ₂, we have;

tan(θ₁) = tan(θ₂)

∴ tan(∠TMR) = tan(∠AMB)

tan\angle X = \dfrac{Opposite \ leg \ length \ to \ reference \ angle}{Adjacent \ leg \ length \ to \ reference \ angle}

tan(\angle TMR) = \dfrac{TR}{MR} = \dfrac{h}{12}

tan(\angle AMB) = \dfrac{AB}{BM} = \dfrac{6}{5}

From tan(∠TMR) = tan(∠AMB), we have;

\dfrac{h}{12} = \dfrac{6}{5}

\therefore h = \dfrac{6 \, ft.}{5 \, ft.} \times 12 \, ft. = 14.4 \, ft.

The height of the tree, h = 14.4 ft.

Therefore, from the proportion \dfrac{h}{12} = \dfrac{6}{5} the height of the tree can be estimated.

3 0
3 years ago
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