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3 years ago

Find the slope of a line perpendicular to the line 8x+4y=2. Thank you! :3

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

Answer:

slope is 1/2

Step-by-step explanation:

4y = -8x + 2

divide by 4

y = -2x + 1/2

-2 ---- 1/2 (perpendicular)

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3 years ago

Which is an irrational number?

Solnce55 [7]

Sqrt(5/3)
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3 years ago

Quick!!!!!!!!!!!!!!!

Degger [83]

Answer: discrete.

Step-by-step explanation:

Discrete variable

It is a variable whose value is evaluated by counting.

Example: Number of books published in a month.

Continuous variable

It is a variable whose value is evaluated by measuring ( not countable).

Example: Distance: 1.52 m

Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.

here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years

So, the random variable described is discrete.

7 0

3 years ago

If you have a bag full of balls. It has 6 blue balls, 6 red balls, and 6 green balls. Let's say you take three balls randomly at

ElenaW [278]

Answer:

1/18 I believe or it should be 1/3. May be wrong, sorry

7 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

Elodia [21]

Answer:

The critical value for this hypothesis test is 6.571.

Step-by-step explanation:

In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.

Then the variance will be, $\sigma^{2}=(5.0)^{2}=25$

The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:

H₀: The population variance is not less than 25.0 minutes, i.e. σ² = 25.

Hₐ: The population variance is less than 25.0 minutes, i.e. σ² < 25.

The test statistics is:

$\chi ^{2}_{cal.}=\frac{ns^{2}}{\sigma^{2}}$

The decision rule is:

If the calculated value of the test statistic is less than the critical value, $\chi^{2}_{n-1}$ then the null hypothesis will be rejected.

Compute the critical value as follows:

$\chi^{2}_{(1-\alpha), (n-1)}=\chi^{2}_{(1-0.05),(15-1)}=\chi^{2}_{0.95, 14}=6.571$

*Use a chi-square table.

Thus, the critical value for this hypothesis test is 6.571.

7 0

4 years ago

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