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anygoal [31]
3 years ago
8

a bag contains 400 coloured counters the counters are either yellow,Brown or green there are 92 yellow counters in the bag the p

robability that Brown counter is chosen from the bag is 0.23 calcuate the number of green counters in the bag
Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0
Is 0.23 a percentage?

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FIND THE VALUE OF X​
Crazy boy [7]

Answer:

By using the rule that the interior angles of any triangle equal 180 we see that:

m<ABC+m<CAB+m<ACB=180°

Therefore,

(2x+15)+(x+10)+(3x+5) = 180°

Now we have an equation and can solve for x:

Combine like terms:

(2x+15)+(x+10)+(3x+5) = 180°

6x+30=180°

6x+30-30=180-30

6x=150

x=25

To check our work just plug in 25 for x in each equation and the sum of those answers should add up to 180:

2x+15

2(25)+15

65

x+10

25+10

35

3x+5

3(25)+5

75+5

80

65+35+80=180

x=25 is valid

Step-by-step explanation:

7 0
3 years ago
Q # 4 Simplify the product
timama [110]
For this case we have the following product:
 (x-4) (x + 3)&#10;
 We must use the distributive property correctly to solve the problem.
 We have then:
 x ^ 2 + 3x - 4x - 12&#10;
 Then, we must add similar terms.
 We have then:
 x ^ 2 - x - 12&#10;
 Answer:
 
The final product is given by:
 
x ^ 2 - x - 12&#10;
 option 2
8 0
3 years ago
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
3 years ago
Between which two consecutive whole numbers does \sqrt{3} 3 ​ lie? Fill out the sentence below to justify your answer and use yo
lyudmila [28]

Answer:

It lies between 5 and 6

Step-by-step explanation:

Two consecutive numbers are numbers that come after each other:

x , x + 1 are consecutive numbers.

3 \sqrt{3} = 3√3 = 5.19615242271

Therefore, from the above calculation, we can see that square root of 3 is a number that is between consecutive numbers 5 and 6

3 0
3 years ago
Factor the expressions<br> Please help
adelina 88 [10]

Answer:

(x + 1)( {6x }^{2}  - 2x)

6 0
2 years ago
Read 2 more answers
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