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zmey [24]
3 years ago
9

A cylindrical container is used to hold drinking water on the sidelines for a football team. The maximum capacity of the contain

er is 26,460 mL. If the height of the container is 60 cm, what is the radius of the cylinder? (1 mL = 1 cm3)
A. 21 cm B. 7.35 cm C. 220.5 cm D. 42 cm
Mathematics
1 answer:
wlad13 [49]3 years ago
6 0
To solve this we are going to use the formula for the volume of a cylinder: V= \pi r^2h
where
V is the volume of the cylinder in cube centimeters 
r is the radius of the cylinder in centimeters 
h is the height of the cylinder in centimeters 

We know for the problem that volume of our cylinder is 26,460 mL. Since 1 mL =1cm^3, the volume of our cylinder is 26460cm^3. We also know for our problem that the height of our cylinder is 60 cm, so h=60. Lets replace those values in our formula and solve for r:
V= \pi r^2h
26460= \pi r^2(60)
26460=60 \pi r^2
r^2= \frac{26460}{60 \pi }
r^2= \frac{441}{ \pi }
r= \sqrt{ \frac{441}{ \pi } }
r= \frac{21}{ \sqrt{ \pi } }
r=11.8

We can conclude that the radius of the football team's <span>cylindrical container is 11.8 cm</span>
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<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

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To find the correct graphic representation we must take into consideration the following:

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From the given quadratic (or parabola) equation we have:

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Have a nice day!

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