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Ber [7]
3 years ago
7

Multiply. start fraction k plus 3 over 4 k minus 2 end fraction dot left parenthesis 12 k squared plus 2 k minus 4 right parenth

esis
Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

\therefore \frac{(k+3)}{(4k-2)}.(12k^2+2k-4)=3k^2+11k+6

Step-by-step explanation:

Factorization of a Quadratic polynomial:

  • In order to factorize ax^2+bx+c we have to find out the numbers p and q such that, p+q = b and pq=ac.
  • Finding the two integers p and q, we rewrite the middle term of the quadratic as px+qx. Then by grouping of the terms we can get desired factors.

Multiplication of two binomial:

(a+b)(c+d)

=a(c+d)+b(c+d)

=(ac+ad)+(bc+bd)

=ac+ad+bc+bd

Given that,

\frac{(k+3)}{(4k-2)}.(12k^2+2k-4)

=\frac{(k+3)}{2(2k-1)}.2(6k^2+k-2)       [ taking common 2]

=\frac{(k+3)}{(2k-1)}.(6k^2+k-2)          [ cancel 2]

=\frac{(k+3)}{(2k-1)}.(6k^2+4k-3k-2)

=\frac{(k+3)}{(2k-1)}.\{2k(3k+2)-1(3k+2)\}

=\frac{(k+3)}{(2k-1)}.(3k+2)(2k-1)

=(k+3).(3k+2)

=3k^2+9k+2k+6

=3k^2+11k+6

\therefore \frac{(k+3)}{(4k-2)}.(12k^2+2k-4)=3k^2+11k+6

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Answer:

a. 6x+1240=12484

b.

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Step-by-step explanation:

a. In the account are 6 deposits of the paid that Tom gets each month and the initial $1240. Let x be the paid Tom gets each month, then:

6x+1240=12484

Solving for x:

6x=12484-1240\\6x=11244\\x=\frac{11244}{6} \\x=1874\\

b)Let x_1 be pounds contained in the first box, x_2 the pound in the second box, x_3 the pounds in the third box and x_4 the pound in the fourth box, then:

x_1+x_2+x_3+x_4=65\\x_2=2x_1\\x_3=x_1+2\\x_4=0.25x_2

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Step 3:

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