Helppppppppppppppppppp

12. A scientist is observing a family of mice. There are four nice which are reproducing and doubling in number every month. Whi

Margaret [11]

Answer:

?

x = the number of months pass right

3 0

2 years ago

Kenny's weight is 6/7 times melvin's weight. what is the ratio of melvin's weight to the total weight of the two boys?

dangina [55]

Answer=7:13

Kenny's Weight*6/7=Melvin's Weight

So, for example, if Melvin's weigh was 7...

Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6

So we can say that Melvin's weight to Kenny's weight is 7:6

The boys total weights would be...
7+6=13

So Melvin's weight over the total weight of the two boys is:

7:13

4 0

3 years ago

Read 2 more answers

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

3 years ago

Can someone help me with this please :)))

Inessa [10]

Answer : 58 square units.

Tip : break the shape down into shapes you can easily find the area of.

I found the area of the two squares on the bottom
They are identical and are both 2 units tall and two units long giving, giving an area of 4, and since there are two of them you can multiply the are by two giving you 8
Next found the area of the remaining shape which is just a rectangle that excludes the two bottom squares which is 10 units long and 5 units tall multiplying to 50
50+8=58

7 0

2 years ago

Read 2 more answers

Please help me, I’m not that smart!

Oxana [17]

Answer:

$\frac{16 {d}^{3} }{ {c}^{2} }$