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Place these numbers in correct order and and simplify 25x^2 +6x^3 -7 +17 -24x^4 +6

Ket [755]

Answer:

$-24x^4+6x^3+25x^2+16$

Step 1:

We need to place the numbers in descending order of the power. Here, $-24x^4$ has the largest power, so that number goes first. We keep doing this until we end up with our final expression, placed in order based on the powers.

$-24x^4+6x^3+25x^2+17-7+6$

Step 2:

We can see that the last three numbers, 17, -7, and 6, don't have variables or powers, so we simplify by adding (and subtracting) them.

$17-7=10\\10+6=16$

Our final equation:

$-24x^4+6x^3+25x^2+16$

3 0

3 years ago

A statistics teacher was interested in the relationship between the number of days students waited to start a project and the sc

seraphim [82]

25.96
85.58
89.22
103.78

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3 years ago

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How do you write 1 and 5 hundredths in standard form

Vedmedyk [2.9K]

1 .05

1 will be put in the ones places where the 5 will be put in the hundredths place.

7 0

3 years ago

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What are the first 10 digits after the decimal point (technically the hexadecimal point...) when the fraction frac17 is written

Nataliya [291]

We happen to have

$\dfrac17 = \dfrac18 + \dfrac1{8^2} + \dfrac1{8^3} + \cdots$

which is to say, the base-8 representation of 1/7 is

$\dfrac17 \equiv 0.111\ldots_8$

This follows from the well-known result on geometric series,

$\displaystyle \sum_{n=1}^\infty ar^{n-1} = \frac a{1-r}$

if $|r|$ . With $a=1$ and $r=\frac18$ , we have

$\displaystyle \sum_{n=1}^\infty \frac1{8^{n-1}} = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac1{1-\frac18} = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac87 = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac17 = \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots$

Uniformly multiplying each term on the right by an appropriate power of 2, we have

$\dfrac17 = \dfrac2{16} + \dfrac{2^2}{16^2} + \dfrac{2^3}{16^3} + \dfrac{2^4}{16^4} + \dfrac{2^5}{16^5} + \dfrac{2^6}{16^6} + \cdots$

Now observe that for $n\ge4$ , each numerator on the right side side will contain a factor of 16 that can be eliminated.

$\dfrac{2^n}{16^n} = \dfrac{2^4\times2^{n-4}}{16^n} = \dfrac{2^{n-4}}{16^{n-1}}$

That is,

$\dfrac{2^4}{16^4} = \dfrac1{16^3}$

$\dfrac{2^5}{16^5} = \dfrac2{16^4}$

$\dfrac{2^6}{16^6} = \dfrac4{16^5}$

etc. so that

$\dfrac17 = \dfrac2{16} + \dfrac4{16^2} + \dfrac9{16^3} + \dfrac2{16^4} + \dfrac4{16^5} + \dfrac9{16^6} + \cdots$

and thus the base-16 representation of 1/7 is

$\dfrac17 \equiv 0.249249249\ldots_{16}$

and the first 10 digits after the (hexa)decimal point are {2, 4, 9, 2, 4, 9, 2, 4, 9, 2}.

3 0

2 years ago

2 1/3 x 6 x 10 (plz explain how)

Flura [38]

21 divided by 3 is 7 then multiplying 7 to 6 which is 42 and after you're multiplying 42 to 10 which is 420.

7 0

4 years ago