3 years ago

Helppppppppppppppppppp

Mathematics

1 answer:

GaryK [48]3 years ago

8 0

shovels=3

bucket =7

a_ 3:7

b- 7:3

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Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

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Answer:

The population of town after 1 year is 25,750 .

Step-by-step explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm n}$

Or, The population after 1 year = 25,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 1}$

Or, The population after 1 year = 25,000 × $(1.03)^{1}$

Or, The population after 1 year = 25,000 × 1.03

∴ The population after 1 year = 25,750

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3 years ago

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Answer:

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Step-by-step explanation:

(-5, -2)(5, -4)

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3 years ago

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Given that loan amount P=20000

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Now to find the interest amount we just plug those values into formula

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Answer:

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he made 15$ in tips.

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4 years ago

How do you turn -8/9 into a decimal and percent?

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You need to divide the numerator by the denominator so it should be 8 divided by 9 to turn it into a percent multiply the decimal you get by 100. Hope this helps!

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3 years ago

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