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Varvara68 [4.7K]
2 years ago
6

Helppppppppppppppppppp

Mathematics
1 answer:
GaryK [48]2 years ago
8 0

shovels=3

bucket =7

a_ 3:7

b- 7:3

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12. A scientist is observing a family of mice. There are four nice which are reproducing and doubling in number every month. Whi
Margaret [11]

Answer:

?

x = the number of months pass right

3 0
2 years ago
Kenny's weight is 6/7 times melvin's weight. what is the ratio of melvin's weight to the total weight of the two boys?
dangina [55]
Answer=7:13

Kenny's Weight*6/7=Melvin's Weight

So, for example, if Melvin's weigh was 7...

Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6

So we can say that Melvin's weight to Kenny's weight is 7:6

The boys total weights would be...
7+6=13


So Melvin's weight over the total weight of the two boys is:

7:13
4 0
3 years ago
Read 2 more answers
A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep
prohojiy [21]
The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
The point P(x,y)
The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
\sqrt{ (x-a)^{2}+ (y-b)^{2} }

Step 2
Find the distance between the point P to the directrix c. It is a vertical distance between y and c, expressed as y-c

Step 3
The equation of parabola is then given as 
\sqrt{ (x-a)^{2}+ (y-b)^{2} }=y-c
(x-a)^{2}+ (y-b)^{2}= (y-c)^{2} ⇒ substituting a, b and c
(x-2)^{2}+ (y--0.5)^{2}  = (y--1.5)^{2}
(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}⇒Rearranging and making y the subject gives

y= \frac{ x^{2} }{2} -2x+1

7 0
3 years ago
Can someone help me with this please :)))
Inessa [10]
Answer : 58 square units.

Tip : break the shape down into shapes you can easily find the area of.

I found the area of the two squares on the bottom
They are identical and are both 2 units tall and two units long giving, giving an area of 4, and since there are two of them you can multiply the are by two giving you 8
Next found the area of the remaining shape which is just a rectangle that excludes the two bottom squares which is 10 units long and 5 units tall multiplying to 50
50+8=58
7 0
2 years ago
Read 2 more answers
Please help me, I’m not that smart!
Oxana [17]

Answer:

\frac{16 {d}^{3} }{ {c}^{2} }

Step-by-step explanation:

{4}^{2}  {c}^{ - 2}  {d}^{3}  {e}^{0}

➡️ 16 {c}^{ - 2}  {d}^{3}  \times 1

➡️ 16 {c}^{ - 2}  {d}^{3}

➡️ 16 \times  \frac{1}{ {c}^{2} }  \times  {d}^{3}

➡️ \frac{16 {d}^{3} }{ {c}^{2} }

8 0
2 years ago
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