Solution :
From the figure,
The coordinates of --
A = (-5,-3)
B = (-6,-1)
C = (-3,-1)
D = (-2,-3)
When it undergoes reflection about x-axis, we have the coordinates of the quadrilateral as
A' = (-5,+3)
B' = (-6,+1)
C' = (-3,+1)
D' = (-2,+3)
Now A'B'C'D' is translated 3 units to right, so the coordinates will be --
A" = (-2,3)
B" = (-3,1)
C" = (0,1)
D" = (1,3)
When the quadrilateral moves third and two units up, we get
A"' = (3,3)
B"' = (2,1)
C"' = (5,1)
D"' = (6,3)
Answer:
C: 8.96
Step-by-step explanation:
We know taht ZX is similar to PQ. We can now set up the ratio of 6.4: 5.12
This ratio gives us .8:1
Multiply VX by the ratio to find its corresponding similar side of RQ
(11.2) * .8 = 8.96
Step-by-step explanation:
4x² + 8x − 7 = 0
4x² + 8x = 7
x² + 2x = 7/4
x² + 2x + 1 = 11/4
(x + 1)² = 11/4
x + 1 = ±√(11/4)
x = -1 ± √(11/4)
Answer:
The correct options are;
A. Construct a perpendicular bisector of the diameter AB
D. Use the compass to draw a circle centered at point C
E. Use the compass to draw two arcs of the same radius centered at point C
F. Use the straightedge to draw diameter AB of the circle
G. Use the straightedge to draw lines connecting the endpoints of the two diameters
Step-by-step explanation:
To draw an inscribed square of a circle, the circle is first constructed. The diameter of the circle is drawn with a straight edge to find the first two vertices of the intended inscribed square. The perpendicular bisector of the diameter is then drawn intersecting the circumference to provide the other two vertices of the square.
The straightedge is then used to draw lines that connect the endpoints of the two diameters to form the inscribed square of the circle.
Answer:
A) -192
B) the difference is 77 ft
Step-by-step explanation: