Answer:
(-6, 0)
Step-by-step explanation:
(x, y) over y=x = (y, x)
so (0, -6) will be (-6, 0).
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
How to solve your question
Your question is
4
+
1
=
2
−
5
4x+1=2x-5
4x+1=2x−5
Solve
1
Subtract
1
1
1
from both sides of the equation
2
Simplify
3
Subtract
2
2x
2x
from both sides of the equation
4
Simplify
5
Divide both sides of the equation by the same term
6
Simplify
Solution
=
−
3
To answer this question you will find the means and the mean absolute deviations and compare them.
The correct answers are
A and C.
Please see the attached picture for the organized work.
