Answer:
<em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>40x-16</em>
Step-by-step explanation:
here,
=4(10x-4)
=40x-16
Answer:
Step-by-step explanation:
The vertices of the trapezoid are the origin along with A(4a, 4b), B(4c, 4b), and C(4d, 0). Find the midpoint of the midsegment of the trapezoid
I'm gonna do it step by step:
parenthesis first, 2-6 is -4 and we can keep the 10 there.
It now looks like this -32+ (-4)(10)
lets multiply -4 and 10 next, the answer is -40.
It now looks like this -32+-40
Simply add, -32 plus -40 is -72.
-72 should be the correct answer, if I'm doing it right
Answer:
Step-by-step explanation:
To calculate a+1/a, we first need to calculate for a.
a = 7 - 4 * ![\sqrt[2]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B3%7D)
square root of 3 = 1.73
a = 7 - 4 * 1.73
a = 7 - 6.9
a = 0.1
0.1 + 1 / 0.1 = 0.1 + 10 = 10.1
Now, in case 4 wasn't being multiplied with the square root of 3, and instead, it was four root of 3, I am gonna do the calculations again:
a = 7 - ![\sqrt[4]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B3%7D)
a = 7 - 1.31
a = 5.69
5.69 + 1 / 5.69 = 5.69 + 0.17 = 5.86
Hope I Helped!
Let x = length of side of the square. Then area of the square is
A(x) = x^2
You are also told that dx/dt = 6 cm/s
Now, you want to find dA/dt when A = 16, i.e., when x = 4.
Since
dx/dt = 6cm/s
and
dA/dx = 16cm/s
dA/dx dx/dt
= dA/dt
dA/dt A' = 2xx'
A' = 2x6cm/s
So we need to solve for x because we are trying to find dA
<span>so
</span>16 = x^(2)
(16)^(1/2) = 4
<span>thus
</span>
A' = 2(4)(6)
A' = 48