18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
Answer:
72
Step-by-step explanation:
As you can see the top - view is a rectangle of 2 by 9 dimensions. Respectively the right - side view is a rectangle of 2 by 4 dimensions. The common dimension among both rectangles would be 2, making this rectangular prism have dimensions 2 by 4 by 9.
Therefore the rectangular prism will have a volume of 2
4
9
2
4
9 = 8( 9 ) = 72 cubic units
Solution : 72 unit cubes
The sketch of the garden and the pond is shown below
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.