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serg [7]
3 years ago
11

Serena bought 3/4 of a kilogram of nuts. she delivered them evenly among 4 containers.

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

Step-by-step explanation:

0.75kg/4c

0.1875kg/c

So there are 0.1875kg per container

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Determine the ordered pair that satisfies the equation, 2x - 8y = -9.
Mama L [17]
You need another equation, other wise x can be anything, and y can be infinitely different solutions.
8 0
3 years ago
Rational numbers with distribute property
Svetradugi [14.3K]

I'm not sure what this means. If you have choices you should list them.

(1/2)*(1/4 + 1/6) is an example of what should be given. There are two ways to solve this.

1. Use the distributive property.

1/2*1/4 + 1/2* 1/6

1/8 + 1/12 Which can be added using the LCD of 24

3/24 + 2/24 = 5/24

Method 2

Add what is inside the brackets first.

1/2 ( 1/4 + 1/6)

1/2(3/12 + 2/12 = 5/12

Now multiply by 1/2

1/2(5/12) = 5*1/(12 * 2) = 5 / 24 Same answer.

4 0
3 years ago
Please help me so much quick :)
Nadusha1986 [10]

Answer:

22 < x < 74

Step-by-step explanation:

Given 2 sides of a triangle with third side x , then

difference of 2 sides < x < sum of 2 sides , that is

48 - 26 < x < 48 + 26 , so

22 < x < 74

6 0
3 years ago
Alejandro is flying a kite, holding his hands a distance of 3.5 feet above the ground
Lemur [1.5K]

Answer: 52.34

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sin23/1=x/125

125sin23=x

x=48.841391... add 3.5 = 52.341391... round to 52.34

7 0
2 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Rudik [331]
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section.  That's
         (change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change =            (change in the value of the function) / (size of the section) = 5/1  =  5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change =           (change in the value of the function) / (size of the section) = 5/1  =  5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0
3 years ago
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