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Nata [24]
3 years ago
15

PLEASE HELP!!!!!! I NEED THIS NOW!!!!!!!

Computers and Technology
2 answers:
Sonbull [250]3 years ago
6 0

Answer: I believe it is a web server.

Explanation:

nadya68 [22]3 years ago
4 0

You need a basic text editor and a web browser.

Explanation:

An internet connection or server is only required when publishing the web page. You can create, edit, and test offline. I so this all of the time. Then when you are done, you upload it to your server and test it fully online before you make it available to the public.

You might be interested in
Drag the tiles to the correct boxes to complete the pairs.
sertanlavr [38]

Answer:

Explanation:

IaaS - storage and network devices

SaaS - software upgrades and patches

MaaS - monitoring tools

PaaS - virtual computing platform

7 0
3 years ago
Illusions in physcology​
qaws [65]

<u>Illusions in Psychology​:</u>

An illusion is a mutilation of the faculties, which can uncover how the human mind typically sorts out and deciphers tangible incitement. Despite the fact that hallucinations twist our impression of the real world, they are commonly shared by a great many people.

They can happen for some reason, for example, the impact of light on an item, inadequate tangible data about an article, or mistakes in a person's handling of tactile subtleties.  

Most deceptions will, in general, hoodwink the eyes, ears, and skin, while there are a few fantasies that may misshape observation because of changes in interior body structures.

The three primary sorts of dreams incorporate optical fantasies, sound-related deceptions, and material figments. Likewise, Illusions give incredible insights into how the cerebrum forms data. Deductively, they can represent an issue for experimental research as they show the manners by which even direct perception can be deluding.

6 0
4 years ago
What is an abstract data type?
Aloiza [94]

Answer:

Abstract data type is a datatype which hides all the implementation details to the end user.

Explanation:

Class is an abstract data type in object oriented programming. Class abstracts both data members and member functions implementation. Here we can hide some confidential data from end user using access specifier "private". We can make end user access only the data which is marked as "public".

example:

public class Calculate

{

private int  salary;

public int workingHours;

public int reatePerHour;

public void Calcuate(){

int total=workingHours*reatePerHour;

cout<<total;

}

}

Here class calculates hides the implementation details of the method "Calculate" .We are abstracting implementation details to the end user using "Class" data type. So it is an AbstarctDataType

8 0
4 years ago
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
4 years ago
Write a for loop to print the numbers 88, 84, 80... 44 on one line
horrorfan [7]

I've included my code in the picture below. Best of luck.

7 0
3 years ago
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