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Alchen [17]
3 years ago
8

The visitor's age is stored in the variable age, the day of the week is stored in a variable day, and the price in dollars is st

ored in the variable price. Which piece of code will correctly decide the price for each ticket.
Computers and Technology
1 answer:
Hoochie [10]3 years ago
4 0

Answer:

If a museum charges different prices based on the day of the week and age of the visitor. The pricing rules are shown below.

- On Tuesday and Thursday children 10 and under get in free ($ 0).

- For all other days and ages the cost is ten dollars ($ 10).

The code in python is;

if (day == 'Tuesday' or day == 'Thursday') and age <= 10:

   price = 0

else:

   price = 10

Explanation:

The logic of the algorithm suggests that that the conditional if-statement assigns zero to the price variable if the day variable is either Tuesday or Thursday and the child's age is 10 or below but assigns 10 to the price variable if the condition is not met.

You might be interested in
What is the primary purpose of the destination address?
ehidna [41]

Answer:

The answer to this question is given below is the explanation section.

Explanation:

"A" option is correct

    It helps the router know where to send the packet.

4 0
3 years ago
What is the opportunity cost of computers when moving from point A to point B? -15 DVDs b. What is the opportunity cost of compu
oee [108]

Answer:

Increasing

Explanation:

Generally in economics, opportunity cost is the benefit that a person, a business, or an investor forgo or missed when he chooses one alternative instead of the other.

Under production, opportunity cost occurs when a producer sacrifice the production of one for the production of another good. Using good X and Y as examples, opportunity cost is measured by the number of units of good Y that the producer gives up in order to produce one or more units of good X.

In the question, the two products used are computers and DVD. The -15, -18 and -20 implies that producing an extra unit of computer by moving from point A to point B, point B to C, and point C to D, 15, 18 and 20 units of DVD respectively have to be given up.

Since 20 is greater than 18 and 18 is also greater than 15, it therefore implies as we produce more computers, the opportunity cost, which are the number of DVDs given up at each point, are increasing.

I wish you the best.

5 0
3 years ago
I need help thanks please!
maw [93]

Answer:

a) to persuade

she is doing this to propose an idea to the boss of the company

6 0
3 years ago
Read 2 more answers
5. Write a program to remove any duplicate letters from a word and display the new word maintaining the original order. For exam
dexar [7]

Answer:

word = input('Enter a single word: ', 's');

n = length(word);

nodupWord = [];

for i = 1:n

  dup = false;

  c = word(i);

  for j = 1:i-1

      if word(j) == c

          dup = true;

          break;

      end

  end

  if ~dup

      nodupWord = [nodupWord, c]; %add the non-duplicate char to end

  end

end

disp(['Adjusted word: ', nodupWord])

Explanation:

The code is in Python.

3 0
3 years ago
Assignment 8: Personal Organizer (in edhesive or python please)
serg [7]

Answer:

eventName = []

eventMonth = []

eventDay = []

eventYear = []

def addEvent():

   userEventName = input("Enter event name: ")

   userEventMonth = int(input("Enter event month (1-12): "))

   userEventDay = int(input("Enter event day(1-31): "))

   userEventYear = int(input("Enter event year (Ex:2020): "))

   userEventMonth = validateMonth(userEventMonth)

   userEventDay = validateDay(userEventMonth,userEventDay,userEventYear)

   

   eventName.append(userEventName)

   eventMonth.append(userEventMonth)

   eventDay.append(userEventDay)

   eventYear.append(userEventYear)

   

def validateMonth(month):

   if month >= 1 and month <= 12:

       return month

   else:

       return 1

def validateDay(month,day,year):

   # invalid days

   if day < 1 or day > 31 :

       return 1

   

   # if the month is february

   if month == 2:

       isleap = False

       if year%4 == 0:

           if year%100 == 0:

               if year%400 == 0:

                   isleap = True

           else:

               isleap = True

       # if the year is leap

       if isleap:

           if day < 30:                

return day

           else:

               return 1

       else:

            if day < 29:

               return day

            else:

               return 1

           

    # month with 31 days

   if month in [1,3,5,7,8,10,12]:

       return day

    # month with 30 days

   if month in [4,6,9,11] and day < 31:

       return day

   else:

       return 1

           

def printEvents():

   print("****** LIST OF EVENTS *********")

   

   months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',

         'August', 'September', 'October', 'November', 'December']

   

   for index in range(len(eventName)):

       print(eventName[index])

       print("Date: "+months[eventMonth[index] -1]+ " " + str(eventDay[index]) + ", " + str(eventYear[index]))

def printEventsForMonth(month):

   months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',

         'August', 'September', 'October', 'November', 'December']

   print("****** EVENTS IN " + months[month -1] + " *********")

   

   for index in range(len(eventName)):

       if eventMonth[index] == month:

           print(eventName[index])

           print("Date: "+months[eventMonth[index] -1]+ " " + str(eventDay[index]) + ", " + str(eventYear[index]))

userChoice = "yes"

while userChoice.upper() != "NO":

   addEvent()

   userChoice = input("Do you want to enter another event? NO to stop: ")

printEvents()

Explanation:

hope this saved somebody from a mental breakdown :)

3 0
3 years ago
Read 2 more answers
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