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Bezzdna [24]
4 years ago
15

Select the correct graph of −4x + 3y = 6. (1 point)

Mathematics
1 answer:
mojhsa [17]4 years ago
6 0

Answer:

Line\ passing\ through\ (-1.5,0)\ and\ (0,2).\\\\Correct\ graph\ is\ attached.

Step-by-step explanation:

The\ given\ equation\ represents\ a\ line\\\\

y-intercept:

Substitute\ x=0\\\\-4\times 0+3y=6\\\\3y=6\\\\y=\frac{6}{3}\\\\y=2\\\\The\ line\ passes\ through\ the\ point\ (0,2).

x-intercept:

Substitute\ y=0\\\\-4x+3\times 0=6\\\\-4x=6\\\\x=-\frac{6}{4}\\\\x=-1.5\\\\The\ line\ passes\ through\ the\ point\ (-1.5,0).

The correct graph is attached.

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The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have
Sonbull [250]

The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

brainly.com/question/27794898

#SPJ4

6 0
2 years ago
What are the steps to solve this problem?
AlladinOne [14]
Area is width times length
Since you know the area and width you can plug them in
100=5*length
length=20
6 0
3 years ago
Read 2 more answers
A truck carries apples, grapes, and blackberries in the ratio of 4:3:4 if the apples weigh 160 pounds, how much the the truckloa
pishuonlain [190]

Answer:the truck load of fruit weigh 440 pounces

Step-by-step explanation:

Let the total weight of the truck load of fruit weigh x pounds.

The truck carries apples, grapes, and blackberries in the ratio of 4:3:4

The total ratio is the sum of the proportions of apples, grapes, and blackberries. It becomes 4+3+4 = 11

if the apples weigh 160 pounds, it means that

4/11 × x = 160

4x/11 = 160

4x = 160×11 = 1760

x = 1760/4

x = 440

4 0
4 years ago
I need help ASAP make sure to plot it correctly
lara [203]

Answer:

1 1/3 and 2 5/6

Step-by-step explanation:

First you find 1 on the number line. Then, since it's divided into sixths, you convert 1/3 to 2/6. Then you can move 2 places to the right from 1.

To find 2 5/6 you first start at 2. Then you move 5 places to the right and plot your point.

4 0
4 years ago
An experiment was conducted to examine two different memorization methods to see which method allows people to remember better.
wlad13 [49]

Question Completion:

SubID  Memory1     Memory2

1                 71                78

2               75                75

3               77                82

4               90                91

5               72                90

6               79                 81

7               84                 75

8               75                 86

9               85                 92

10              75                 77

11               72                 92

12               76                87

13               77                93

14               90                94

15               84                78

16               73                92

17               75                85

18               87                86

19               75               95

20              70               94

21               72               75

22              90               84

23               81               94

24               87               82

25              90               82

26              87               79

27              78               94

28              78               79

29              70               82

30               81               80

31               80               78

32              90               87

33              83               90

34               81               85

35              73               88

36              82               82

37              84               94

38              85               86

39              77               94

40               82              83

Answer:

Since the mean of Memory1 (reciting method) (79.8) is smaller than the mean of Memory2 (imagery method) (85.5), we can conclude that there is a significant difference in memory performance between the reciting method and the imagery method.

Step-by-step explanation:

a) Data and Calculations:

SubID  Memory1     Memory2

1                 71                78

2               75                75

3               77                82

4               90                91

5               72               90

6               79                81

7               84                75

8               75                86

9               85                92

10              75                77

11               72                92

12              76               87

13              77               93

14              90               94

15              84               78

16              73               92

17              75               85

18              87               86

19              75               95

20             70               94

21              72               75

22             90               84

23              81               94

24             87               82

25            90               82

26             87               79

27             78               94

28             78               79

29             70               82

30              81               80

31              80               78

32             90               87

33             83               90

34              81               85

35             73               88

36             82               82

37             84               94

38             85               86

39             77               94

40             82               83

Total     3,193          3,421

Mean     79.8            85.5

Difference in means = 5.7 (85.5 - 79.8)

7 0
3 years ago
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