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Artyom0805 [142]
3 years ago
9

CAN SOMEONE GIVE ME THE STEPS I HAVE THE ANSWERS I JUST NEED THE STEPS

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Problem 1:

1) 3/5x-1 x 3/4=9/10

3x/5-1 x 3/4=9/10

2) 3x/5-1 x 3/4=9/10

3x/5-3/4=9/10

3) 3x/5-3/4=9/10

+3/4 +3/4

4) 3x/5=33/20

5) 5 x 3x/5= 5 x (33/20)

6) 3x=33/4

7) 3x=33/4

/3 /3

8) x=11/4

Problem 2:

1) 6/7+2/5x=-4/5

6/7+2x/5=-4/5

2) 6/7+2x/5=-4/5

-6/7 -6/7

3) 2x/5= --58/35

4) 5 x 2x/5= 5 x (--58/35)

5) 2x= --58/7

6) 2x= --58/7

/2 /2

x= --29/7

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Answer:

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

Step-by-step explanation:

Representemos el número de cajas como

A = caja estándar de frambuesas

B = caja de lujo de frambuesas

Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.

A + B = 135 ......... Ecuación 1

B = 135 - A

7A + 10B = 1100 ........... Ecuación 2

Sustituir

135 - A para B en la ecuación 2

7A + 10 (135 - A) = 1100

7A + 1350 -10A = 1100

7A - 10A = 1100-1350

-3A = - 250

A = 250/3

A = 83.33 cajas

Sustituye 83.33 por A en la ecuación 1

A + B = 135

83,33 + B = 135

B = 135 - 83.33 = 51.67 cajas

Por lo tanto, vendió,

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

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