The simplified form of 3 over 2x plus 5 + 21 over 8 x squared plus 26x plus 15 is <span>6 over the quantity 4 x plus 3.
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The solution would
be like this for this specific problem:
( 3 /( 2x+5 )) + ( 21 / (8x^2 + 26x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (8x^2 + 20x + 6x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (4x(2x + 5) + 3(2x + 5))
= ( 3 /( 2x+5 )) + ( 21 /(2x + 5)(4x + 3)
= [ 3 (4x + 3) + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 9 + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 30 ] /(2x + 5)(4x + 3)
= 6(2x + 5) /(2x + 5)(4x + 3)
= 6 / (4x + 3)
<span>I am hoping that
this answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.</span>
1. Given
2. AD is parallel to BC
3. ∠3 ≅ ∠2
4. transitive property of congruence
5. Definition of bisect
Answer:
no
Step-by-step explanation:
it does not work r÷eeeeeeeeeeeeeeee eeeeeeeeeeeeeeee eeeeeeeeeeeeeeee
For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
√84= √4•√21= final answer is
±2√21