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slega [8]
3 years ago
14

If x,y and z are positive integers and 3x=4y=7z, then the least possible value of x+y+z=?

Mathematics
2 answers:
Anettt [7]3 years ago
6 0
Integers
positive
okso therefor
3x=some number
4y=some number
7y=some number

therefor, this 'some number' must have factors of 3,4,7

find greatest common multiplule
3=3
4=2 times 2
7=7
3 times 2 times 2 time s7=84



3x=4y=7z=84
solve
3x=84
divide 3
x=28

4y=84
divide 4
y=21

7y=84
divide 7
y=12


so
x+y+z=28+21+12=61
Marrrta [24]3 years ago
6 0
Multiply 3x4x7 to get the lowest number they will all go into. Then divide by the number you're trying to figure out (exp. 84/3=28) X=28 y=21 z=12 :)
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see the attached figure to better understand the problem

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