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galben [10]
3 years ago
12

The trapezoid has an area of 115 sq. units.

Mathematics
1 answer:
Scilla [17]3 years ago
3 0

Answer:

Its has an area 115 square ft

Step-by-step explanation:

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Which is the logarithmic form of 25 = 52?
goldfiish [28.3K]

Answer: 5^5=52

Step-by-step explanation:

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What is the Area of 20ft & 24ft?
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480

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Violet knows that her subscription rate for the basic tier of cable television increased from $18.20 to $19.50 at some point dur
mezya [45]
The 2 equations are
18.20x+19.50y=230.10
and
x+y=12
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x=(12-y)
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7 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
Hey someone help me with this please
OverLord2011 [107]

Answer:

d

Step-by-step explanation:

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If I helped please vote brainliest

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