Question

HEN

Answer 1

Pressure of the nitrogen gas is 2290 kPa.

Explanation:

Using the ideal gas equation, we can find the pressure of the gas using the equation as,

PV = nRT

Where P is the pressure = ?

V is the volume = 3,456 ml = 3.456 L

n is the number of moles = $\frac{given mass}{molar mass}$  = $\frac{45.2g }{14 g/mol}$  = 3.2 mol

R is the gas constant  = 0.08205 L atm  K⁻¹ mol⁻¹

T is the temperature = 25 + 273 = 298 K

Now, rewriting the equation, we will get,

P = $\frac{nRT}{V}$

= $\frac{3.2 \times 0.08205\times 298 K }{3.456 L}$

= 22.6 atm

Now Pressure in 22.6 atm is converted as 2290 kPa.