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3 years ago

15

Alberto is setting now for boards of lumber the length of the boards are 4.5 feet 4.52 feet and 4 feet and four. 555 feet or did

the links from the longest to shortest

1 answer:

Dahasolnce [82]3 years ago

4 0

Answer:

No

Step-by-step explanation:

Did the links from the longest to shortest?: NO

Please have a loọk at this link below from the longest to shortest:

4.555 , 4.52 , 4.5 , 4

Hope it will find you well

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Find the circumference whose radius is 20cm take 3.14

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Step-by-step explanation:

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Q =3x2+5x-2 R = 2 – x2 S = 2x + 5 Find Q – [R + S] Show all of the steps.

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Answer:

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Step-by-step explanation:

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3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

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3 years ago

Which of the following represents a number between 0.01 and 0.001?

FinnZ [79.3K]

To compare the numbers, go from left to right examining the numbers carefully. so look at a., 3.7 can be written as 3.700, if u look, 3 and 0, it is definetly bigger than 0.01 and 0.001

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3 years ago