Answer:
16
Step-by-step explanation:
To solve, we can use an equation finding the average of the siblings'ages.

Answer:
Type I error.
Step-by-step explanation:
The decision to shut the process is triggered by the conclusion that the average height is significantly different from 66 mm.
This means that the null hypothesis, that states that the average height is not significantly different from 66 mm (μ=66), has been rejected.
If the null hypothesis is rejected, the error that can have been made is to reject a true null hypothesis, when the process is functioning to specification and the average length is not significantly different from 66.
This is a Type I error, that happens when a true null hypothesis is rejected.
Answer:
Step-by-step explanation:
D
Half the x-coefficient is -3, so the equation needs to be rearranged into a form that looks like
x² -6x +(-3)² + [something]
You can get there by adding and subtracting 9 from the original equation.
y = x² -6x +9 +7 -9 . . . . . 9 added and subtracted
y = (x² -6x +9) -2
The quantity in parentheses is a perfect square, so we can write the equation in the desired form as ...
y = (x -3)² -2
<em>Solu</em><em>tion</em><em>:</em>
<em>hypotenuse</em><em>=</em><em>p</em>
<em>perpe</em><em>ndicular</em><em>=</em><em>m</em>
<em>base</em><em>=</em><em>n</em>
<em>According</em><em> </em><em>to</em><em> </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>
<em>h^</em><em>2</em><em>=</em><em>p^</em><em>2</em><em>+</em><em>b</em><em>^</em><em>2</em>
<em>So</em><em> </em><em>the</em><em> </em><em>right </em><em>an</em><em>swer</em><em> </em><em>of</em><em> </em><em>you</em><em>r</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>m^</em><em>2</em><em>+</em><em>n^</em><em>2</em><em>=</em><em>p^</em><em>2</em>
<em>Right</em><em> </em><em>ans</em><em>wer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>A</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>