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telo118 [61]
3 years ago
8

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the lateral area of the pyramid.

Mathematics
2 answers:
Tanya [424]3 years ago
6 0
72sq. units lllllllllllllllllllllllllllllllllllllllllllllll
notka56 [123]3 years ago
5 0

Answer:

Option C is correct

the lateral area of the pyramid is, 72 sq. units

Step-by-step explanation:

Lateral surface area(S) of the pyramid is given by:

S = 6 \cdot \frac{1}{2}(\text{Base} \cdot \text{Slant height})

As per the statement:

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

⇒s = 4 units, slant height = 6 units

Substitute in [1] we have;

S = 6 \cdot \frac{1}{2} \cdot 4 \cdot 6 = 72 square units

Therefore,  the lateral area of the pyramid is, 72 sq. units

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Your friend incorrectly says the solution to the equation 11.2y - 7.4y=141.36 is y=7.6 what error did your friend make? A) Divid
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The correct answer is: D) Subtracted like terms incorrectly

Step-by-step explanation:

Given

11.2y - 7.4y=141.36

The terms 11.2y-7.4y need to be subtracted. But option b is to add them. We will add them and then solve the equation to see if its right.

So adding 11.2y-7.4y

18.6y=141.36

Dividing both sides by 18.6

\frac{18.6y}{18.6}=\frac{141.36}{18.6}\\y=7.6

so by adding the terms instead of subtracting we get y=7.6.

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Dividing both sides by 3.8

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The correct answer is: D) Subtracted like terms incorrectly

Keywords: Linear equation, Expression

Learn more about linear expressions at:

  • brainly.com/question/4460262
  • brainly.com/question/4464845

#LearnwithBrainly

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