Answer:
![\{(0,0) (0,9) (9,0)\}](https://tex.z-dn.net/?f=%5C%7B%280%2C0%29%20%280%2C9%29%20%289%2C0%29%5C%7D)
Step-by-step explanation:
Given
See attachment for matrix
From the attachment, we have the following vertices
![(x_3,y_3) = (3,0)](https://tex.z-dn.net/?f=%28x_3%2Cy_3%29%20%3D%20%283%2C0%29)
When scaled by 3T, we have the following:
![(x_1,y_1) =3 * (0,0)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D3%20%2A%20%280%2C0%29)
![(x_1,y_1) =(0,0)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%280%2C0%29)
![(x_2,y_2) = 3 * (0,3)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%3D%203%20%2A%20%280%2C3%29)
![(x_2,y_2) = (0,9)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%3D%20%280%2C9%29)
![(x_3,y_3) = 3 *(3,0)](https://tex.z-dn.net/?f=%28x_3%2Cy_3%29%20%3D%203%20%2A%283%2C0%29)
![(x_3,y_3) = (9,0)](https://tex.z-dn.net/?f=%28x_3%2Cy_3%29%20%3D%20%289%2C0%29)
Hence, the vertices are:
![\{(0,0) (0,9) (9,0)\}](https://tex.z-dn.net/?f=%5C%7B%280%2C0%29%20%280%2C9%29%20%289%2C0%29%5C%7D)
Answer:
![\frac{5}{6} = x](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D%20%3D%20x)
Step-by-step explanation:
![\frac{3}{7}x = \frac{5}{14} \\ \\ \frac{5}{14} \div \frac{3}{7} = \frac{5}{14} \times \frac{7}{3} = \frac{35}{42} = \frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B7%7Dx%20%3D%20%5Cfrac%7B5%7D%7B14%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B5%7D%7B14%7D%20%5Cdiv%20%5Cfrac%7B3%7D%7B7%7D%20%3D%20%5Cfrac%7B5%7D%7B14%7D%20%5Ctimes%20%5Cfrac%7B7%7D%7B3%7D%20%3D%20%5Cfrac%7B35%7D%7B42%7D%20%3D%20%5Cfrac%7B5%7D%7B6%7D)
Use multiplication [inverse of division] to figure this out.
* 2⅓ = 7⁄3
I am joyous to assist you anytime.
Plan d as oval if la candid dad 12’xpp
Answer:
substitute y = mx +b = (2/3)x -2
Step-by-step explanation:
slope intercert form looks like this
y = mx + b
m is the slope
b is the y intercept
The line intercepts the y at -2
To find slope, pick 2 points to find the slope
m = (y2 - y1)/(x2-x1)
i select point 1 (0,-2) and point 2 (3,0)
m = (0-(-2))/(3-0) = (2)/3
substitute y = mx +b = (2/3)x -2
Okay so you do not really need the circle equation. if you make a triangle with it's x length as 3 and it's y length as 4, you will be able to find the third length. Do Pythagorean theorem to find the hypotenuse.
the hypotenuse will be five after you calculate it.
sin is opposite over hypotenuse or Y over R
so... the sin is 4/5
make sure you know what quadrant your triangle is in for the negatives