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Aliun [14]
3 years ago
5

If ax + x^2 = y^2 -at , what is the value or x and y?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

dx. = yex ⇒ dy y. ∫. = x ... 2 xx dx. ∫. , i.e. yx = 4. 4 x c. +. Hence y = 3. 4 x c x.

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Arturiano [62]
It would be 6/20 = $0.30

30 cents or $ 0.30 
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3 years ago
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If-1 is a root of f), which of the following must be true?
ANEK [815]

Answer:

A factor of f(x) is (x + 1).

Step-by-step explanation:

When we put x+1= 0 then we  get the value x= -1

This value is then put into the function to find out whether it is a root or not. For a root  to exist it must not have a remainder or the remainder must be zero.

Suppose the function is

F(x)= 2x³ - 42x - 40

f(-1)= 2(-1)³ - 42(-1) - 40

f(-1)= -2 + 42- 40

f(-1)= 0

This gives -1 as the root of the function.

6 0
2 years ago
Given the function f(x)=9-2x, find x when f(x)=25<br><br> -41<br> 17<br> -8
tatyana61 [14]

Answer:

x = -8

Step-by-step explanation:

Set the function f(x)=9-2x equal to 25, and then solve the resulting equation for x:

9 - 2x = 25.

Isolate the -2x term by subracting 9 from both sides:

-2x = 16

Finally, solve for x by dividing both sides by -2:

x = -16/2, or x = -8

3 0
3 years ago
Read 2 more answers
What is the standard form of a quadratic function passing through the points (2,4) , (3,5) and (4,3)
Sladkaya [172]

The standard form of a quadratic function is y = 3/2x² + 17/2x - 7

<h3>How to determine the quadratic equation?</h3>

From the question, the points on the quadratic equation are given as

(2,4), (3,5) and (4,3)

The standard form of a quadratic equation is represented as

y = ax² + bx + c

So, we have

Point (2,4):

4a + 2b + c = 4

Point (3,5):

9a + 3b + c = 5

Point (4,3):

16a + 4b + c = 3

Solving using an online calculator. we have

a = 3/2, b = 17/2 and c = -7

Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c

y = 3/2x² + 17/2x - 7

Hence, the equation is y = 3/2x² + 17/2x - 7

Read more about quadratic equation at

brainly.com/question/1214333

#SPJ1

5 0
1 year ago
Solve. x 5 + 3 = 2 A) -5 B) 25 C) 5 D) - 1/5
vladimir1956 [14]
Just isolate the variable x.
x*5+3=2
5x=-1
x=-1/5
3 0
3 years ago
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