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3 years ago

`we discussed benzene rings in this lesson. so, consider the compound chlorobenzene. how many carbon atoms would it have?

1 answer:

4 0

Chlorobenzene would essentially be a benzene ring that is substituted with chlorine. Thus it would have 6 carbon atoms, in its molecular formula.

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Explain why the atomic mass of an element is usually not given as a whole number even though each individual atom of the element

Zinaida [17]

An atomic mass is the sum of the protons and neutrons of a given element. The atomic mass is given it what is called a weighted average of all the different kinds of that element. Take carbon for example. It has carbon-12, carbon-13, and carbon-14. The reason its atomic weight is so close to 12 (12.011 ish) is because carbon-12 is by far the most common, and carbon-13 and -14 are so uncommon, that the weighted average is close to 12, but not exactly 12.

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4 years ago

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likoan [24]

Answer:

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Explanation:

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3 years ago

Systematic error is defined as:_______.

Andru [333]

Answer:

The correct answer is option d.

Explanation:

It is defined as repeatable and consistent error associated with a faulty equipment. It a fixed amount of deviation of a measurement from the actual measurement.

These error usually caused by incorrectly calibrated instruments or by an incorrect use of the instruments.

For example: observational error , interference of environment etc.

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4 years ago

Can you substitute evaporated milk for condensed milk

alex41 [277]

Yes because condensed milk and evaporated milk are similar to one another. However, there won’t be the same sweet flavor but the texture is the same.

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3 years ago

Consider the following reaction at 298.15 K: Co(s)+Fe2+(aq,1.47 M)⟶Co2+(aq,0.33 M)+Fe(s) If the standard reduction potential for

fgiga [73]

Answer:

The correct answer is 0.186 V

Explanation:

The two hemirreactions are:

Reduction: Fe²⁺ + 2 e- → Fe(s)

Oxidation : Co(s) → Co²⁺ + 2 e-

Thus, we calculate the standard cell potential (Eº) from the difference between the reduction potentials of cobalt and iron, respectively, as follows:

Eº = Eº(Fe²⁺/Fe(s)) - Eº(Co²⁺/Co(s)) = -0.28 V - (-0.447 V) = 0.167 V

Then, we use the Nernst equation to calculate the cell potential (E) at 298.15 K:

E= Eº - (0.0592 V/n) x log Q

Where:

n: number of electrons that are transferred in the reaction. In this case, n= 2.

Q: ratio between the concentrations of products over reactants, calculated as follows:

$Q = \frac{ [Co^{2+} ]}{[Fe^{2+} ]} = \frac{0.33 M}{1.47 M} = 0.2244$

Finally, we introduce Eº= 0.167 V, n= 2, Q=0.2244, to obtain E:

E= 0.167 V - (0.0592 V/2) x log (0.2244) = 0.186 V

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4 years ago