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yKpoI14uk [10]
3 years ago
11

What is an equation in slope-intercept form of the line that passes through the points (−2, −2) and (1, 7)?​

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

slope of line (m) : 3

Step-by-step explanation:

P1: (-2 , -2)

P2: ( 1, 7)

the slope formula is

m = ( Y2-y1)/(x2-x1)

m = (-2-7)/(1+3)

m=3

Equation of line is y=mx+b

Using P2 ( 1,7)

7 = 3(1) + b

7 = 3+ b

7-3 = b

b = 4

so that, line equation is:

y = 3x +4

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Answer: $2,009

Step-by-step explanation:

345 + 125 = 470

470 + 21 = 491

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1/120

<h3>Explanation:</h3>

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Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen
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Answer:

C. (-13, -7)

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The location of a point O(x, y) that divides a line AB with location A(x_1,y_1) and B(x_2,y_2) in the ratio m:n is given by:

x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7

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Step-by-step explanation:

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Let x - width, y - length.

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