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2 years ago

For any parallelogram what is not always true

Mathematics

2 answers:

tresset_1 [31]2 years ago

7 0

Answer:

The diagonals are congruent.

Step-by-step explanation:

enyata [817]2 years ago

4 0

Answer:

1) The diagonals are congruent.

3) The opposite angles are congruent.

4) The opposite sides are parallel.

Step-by-step explanation:Two pairs of opposite sides are congruent. The diagonals are perpendicular to each other. 4 In parallelogram QRST, diagonal is drawn. Which statement must always be true?

if it does not work sorry

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Step-by-step explanation:

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3 years ago

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What is the proportion for x

Artist 52 [7]

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3 years ago

What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?

Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

Finding the Interest

The sum of principal and interest is called an amount.

From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

plug the values

⇒ $\sf{14550 = 6000 + Interest}$

Swap the sides of the equation

⇒ $\sf{6000 + Interest = 14550}$

Move 6000 to right hand side and change its sign

⇒ $\sf{Interest = 14550 - 6000}$

Subtract 6000 from 14550

⇒ $\sf{Interest = \: 8550 \: }$

Interest = $ 8550

Finding the rate 

${ \boxed{ \sf{Rate = \frac{Interest \times 100}{Principal \times Time}}}}$

plug the values

⇒ $\sf{ Rate = \frac{8550 \times 100}{6000 \times 10} }$

Calculate

⇒ $\sf{Rate = \frac{855000}{60000} }$

⇒ $\sf{Rate = 14.25 \: \% \: }$

Hope I helped!

Best regards!!

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3 years ago

The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ

Rudik [331]

This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181

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4 years ago

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Natasha2012 [34]

Answer:

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Step-by-step explanation:

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3 years ago