Question:
Which system has the same solution as the teacher's system?
Systems of equations that have the same solution are called equivalent systems.We are given with a system of two equations, we can make an equivalent system by substituting one equation by the sum of the two equations.
Given System:
<span>
8x-16y=14</span>→eq.1
−x+5y=−3→eq.2<span>
Teacher's Solution:
From eq.2
x = 5y + 3
Substituting the value of x in eq.1
We get,
</span> 8(5y + 3) - 16y = 14
40y + 24 - 16y = 14
24y + 24 = 14
24y = 14-24
24y = -10
y = -10/24
y = -5/12
Substituting y-value in eq.2,
−x+5(-5/12) = −3
-x -25/12 = -3
-x = -3 + 21/12
-x = 15/12
x = -5/4
<span>Fabiano:
</span> 3x−15y=<span>9
</span> 8x−16y=−<span>7
</span>Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x+7/16
Placing both equations equal to each other,
1/5x - 3/5= 1/2x+7/16
1/5x -1/2x = 7/16 +3/5
-3/5x = 83/80
x = -83×5/80×3
x = -415/240
x = -83/48
This doesnt matches the teachers solution so we will move to sonali.
<span>Sonali
</span> −x+5y=−<span>3
</span> −4x+8y=−7
Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x -7/8
Placing both equations equal to each other,
1/5x - 3/5 = 1/2x -7/8
1/5x -1/2x = -7/8 +3/5
-3/10x = -11/40
x = 110/120
x = 11/12
This doesn't match the teacher's solution either, so we will conclude that none of the solutions to the system of equation has the same answer as the teacher.
S = 10 + r. Please give me a brainliest if you found this helpful:)
<h3>
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➷ Use the formula: distance = speed x time
Jordan's distance = 55 x 6
Jordan's distance = 330 miles
Matt's distance = 60 x 3
Matt's distance = 180 miles
330 + 180 + 82 = 592
In short, the answer is 592 miles
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
Question 7: Option 1: x = 33.5°
Question 8: Option 3: x = 14.0°
Step-by-step explanation:
<u>Question 7:</u>
In the given figure, the value of perpendicular and hypotenuse is given, so we have to use any trigonometric ratio to find the value of angle as the given triangle is a right-angled triangle
So,
Perpendicular = P = 32
Hypotenuse = H = 58
So,

Rounding off to nearest tenth
x = 33.5°
<u>Question 8:</u>
In the given figure, the value of Base and Perpendicular is given, we will use tangent trigonometric ratio to find the value of x
So,
Perpendicular = P = 5
Base = B = 20
So,

Rounding off to nearest tenth
x = 14.0°
Keywords: Right-angled triangle, trigonometric ratios
Learn more about trigonometric ratios at:
#LearnwithBrainly