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3 years ago

Consider the following function.

Mathematics

1 answer:

shtirl [24]3 years ago

3 0

Help ASAP only right answers only no spam don’t answer if you don’t know

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A shirt is 39 dolars and on sale for 33% off and what is the discount and sale price

DanielleElmas [232]

33%=0.33

33% of 39=0.33*39=12.87
discount is 12.87
minus
39-12.87=26.13

sale price=$26.13
discount=$12.87

4 0

3 years ago

Read 2 more answers

Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100μ=100 and a standard deviation sigma

Ksivusya [100]

Answer:

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 114, \sigma = 86$

Find the probability that a randomly selected adult has an IQ between 86 and 114.

Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So

X = 114

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{114 - 100}{20}$

$Z = 0.7$

$Z = 0.7$ has a pvalue of 0.7580

X = 86

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{86 - 100}{20}$

$Z = -0.7$

$Z = -0.7$ has a pvalue of 0.2420

0.7580 - 0.2420 = 0.5160

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

3 0

4 years ago

What is an equation of the line that passes through the points (6, 4) and(6,−6)?

Tems11 [23]

Answer:

Step-by-step explanation:

6 0

2 years ago

An object has a constant acceleration of 30 ft/sec2, an initial velocity of -10 ft/sec, and an initial position of 4 ft. Find th

Pavel [41]

Let $a(t),v(t),s(t)$ be the acceleration, velocity, and position functions, respectively. Then

$v(t)=s'(t)$
$a(t)=v'(t)=s''(t)$

Since the acceleration is a constant 30 ft/s^2, you have

$a(t)=s''(t)=30$
$\displaystyle\int s''(t)\,\mathrm dt=\int30\,\mathrm dt$
$\displaystyle s'(t)=v(t)=30t+C_1$

You're told that the initial velocity is $v(0)=-10$ , so you get

$-10=30(0)+C_1\implies C_1=-10$

Now $s'(t)=30t-10$ . Integrating once more, you find

$\displaystyle\int s'(t)\,\mathrm dt=\int(30t-10)\,\mathrm dt$
$s(t)=15t^2-10t+C_2$

and since $s(0)=4$ , you get

$4=15(0)^2-10(0)+C_2\implies C_2=4$

which means the exact position function is

$s(t)=15t^2-10t+4$

7 0

4 years ago

Jesse owns a sporting goods store that sells skis and snowboards. The store earns a profit of $52 for each ski sold and a profit

kvv77 [185]

Jesse sold 9 snowboards.

3 0

4 years ago