Answer:
B. (1,5) and (5.25, 3.94)
Step-by-step explanation:
The answer is where the 2 equations intersect.
We need to solve the following system of equations:
y = -x^2 + 6x
4y = 21 - x
From the second equation:
x = 21 - 4y
Plug this into the first equation:
y = -(21 - 4y)^2 + 6(21 - 4y)
y = -(441 - 168y + 16y^2)+ 126 - 24y
y = -441 + 168y - 16y^2 + 126 - 24y
16y^2 + y - 168y + 24y + 441 - 126 = 0
16y^2 - 143y + 315 = 0
y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)
y = 5, 3.938
When y = 5:
x = 21 - 4(5) = 1
When y = 3.938
x = 21 - 4(3.938) = 5.25.
Answer:
Easy lol mzvcn=48
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
8/-4 ÷ -3/9
8/-4 × 9/ -3 = 6
x° = 14°, y° = 14°; Use vertical and supplementary angles.
Step-by-step explanation:
The image of the answer is attached below.
In the given image two lines are parallel with transversal.
(9x + 12)° and ∠1 are vertically opposite angles.
Vertically opposite angles are equal.
∠1 = (9x + 12)°
Consecutive interior angles are supplementary.
(9x + 12)° + 3x° = 180°
⇒ 12x° = 168°
⇒ x° = 14°
Sum of the adjacent angles in a line are supplementary.
3x° + (4y – 10)° = 180°
⇒ 3(14)° + 4y° – 10° = 180°
⇒ 4y° = 148°
⇒ y° = 14°
Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.
53y-42y=55
11y=55
Y=55/11 =5