Answer:
8
Step-by-step explanation:
23 students -15 students =8students
I think we need a trapazoid
Answer:
Since k is constant (the same for every point), we can find k when given any point by dividing the y-coordinate by the x-coordinate.
so i assume it could be 162 sorry if i am wrong let me know if it is right or not
Remember, order of operations
exponent before multiply
so 4x^5/6=4 times x^5/6
simplify the x^5/6 first
remember
![x^\frac{m}{n}=\sqrt[n]{s^m}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Bs%5Em%7D)
so
![x^\frac{5}{6}=\sqrt[6]{x^5}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7B5%7D%7B6%7D%3D%5Csqrt%5B6%5D%7Bx%5E5%7D)
so
![4x^\frac{5}{6}=4\sqrt[6]{x^5}](https://tex.z-dn.net/?f=4x%5E%5Cfrac%7B5%7D%7B6%7D%3D4%5Csqrt%5B6%5D%7Bx%5E5%7D)
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Answer:
m = 1
Step-by-step explanation:
We can suppose that the number we are looking for is for example 5.
(we can do so because the probability is the same for each number - it'sna fair dice)
For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).
For the second toss the probability we have 5 is again 1/6.
For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)
Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.
We can see that m = 1.
