Ask question

Ask question

All categories

3 years ago

6

Enrique has $50 in his lunch account and spends $5 per day from the account. Maya has $46 in her lunch account and spends $4 per

day from the account. Which equations model the situation?
50 – 5x = y and 46 – 4x = y

5x + 50 = y and 4x + 46 = y

5x – 50 = y and 4x – 46 = y

5 – 50x = y and 4 – 46x = y

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

50 – 5x = y and 46 – 4x = y, is your answer

You might be interested in

How do I get the answer for exponents? Please explain step by step to get marked!

ioda

Answer:

4900

Step-by-step explanation:

70^2 means 70*70

70*70=4900

3 0

2 years ago

Read 2 more answers

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Simplify sec(t)cot(t) to a single trig function or constant with no fractions

lana66690 [7]

Answer:

make it make sense then could answer

4 0

2 years ago

A sixth grade class has 12 boys and 24 girls. Q: For every 2 boys, there are 4 girls, do you agree with this statement? Explain

dimaraw [331]

Agree....There are 12 boys and every 2 = 6 groups 6x2
There are 24 girls and every 4 to the 2 =6 groups 6x4

7 0

3 years ago

Read 2 more answers

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5

Anuta_ua [19.1K]

Answer:

$y = \frac{3}{2} x-11$

Step-by-step explanation:

We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation is $y = - \frac{2}{3} x+5$ .

We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be $\frac{3}{2}$ .

Then, we will find the y-intercept of the line using the standard equation of a line:

$y=mx+c$

$1=\frac{3}{2} (8)+c$

$c=-11$

Therefore, the equation of the line will be $y = \frac{3}{2} x-11$ .

7 0

3 years ago

Read 2 more answers