Question

PLEASE HELP ME! & FIND Y

Answer 1

Answer:

Y ≈ 59.0°

Step-by-step explanation:

Using the Cosine Rule in Δ XYZ

cosY = $\frac{x^2+z^2-y^2}{2xz}$

Here x = 22, y = 20, z = 22, then

cosY = $\frac{22^2+18^2-20^2}{2(22)(18)}$

         = $\frac{484+324-400}{792}$

        = $\frac{408}{792}$ , thus

Y = $cos^{-1}$ ( $\frac{408}{792}$ ) ≈ 59.0° ( to the nearest tenth )