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boyakko [2]
2 years ago
11

PLEASE HELP ME! & FIND Y

Mathematics
1 answer:
zavuch27 [327]2 years ago
4 0

Answer:

Y ≈ 59.0°

Step-by-step explanation:

Using the Cosine Rule in Δ XYZ

cosY = \frac{x^2+z^2-y^2}{2xz}

Here x = 22, y = 20, z = 22, then

cosY = \frac{22^2+18^2-20^2}{2(22)(18)}

         = \frac{484+324-400}{792}

        = \frac{408}{792} , thus

Y = cos^{-1} ( \frac{408}{792} ) ≈ 59.0° ( to the nearest tenth )

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