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aalyn [17]
3 years ago
3

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t=0, th

e resulting mass-spring system is disturbed from its rest state by the force F(t)=140cos(8t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Physics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

K= 1000 N-m

Explanation:

It is assumed that we asked to find the spring constant k of the spring

We know that under equilibrium condition

weight of the object = force applied by the spring

given m =10 Kg

x= extension in the spring = 9.8 cm

mg=kx

10\times9.8=k\times9.8\times10^(-2)

K= 1000 N-m

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Starting from rest, a runner reaches a speed of 2.8 m/s in 2.1 s. In the same time 2.1 s time, a motorcycles increases speed fro
maw [93]

Answer:

a) Acceleration of runner is 1.33 m/s²

b)  Acceleration of motorcycle is 2.85 m/s²

c) The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{2.8-0}{2.1}\\\Rightarrow a=1.33\ m/s^2

Acceleration of runner is 1.33 m/s²

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{43-37}{2.1}\\\Rightarrow a=2.85\ m/s^2

Acceleration of motorcycle is 2.85 m/s²

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{2.8^2-0^2}{2\times 1.33}\\\Rightarrow s=2.94\ m

The runner moves 2.94 m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{43^2-37^2}{2\times 2.85}\\\Rightarrow s=84.21\ m

The motorcycle moves 84.21 m

The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.

3 0
3 years ago
Which of the following is an example of the concepts of growth and development functioning together?   
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Hello there.

<span>Which of the following is an example of the concepts of growth and development functioning together?   <span>
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7 0
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is the light transmitted by a filter brighter than, less brighter than, or the same brightness as the light that hits it? explai
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The light transmitted by a filter is <em>less bright </em>than the light that hits it.

A filter only absorbs/removes part of the light that hits it.  That means it removes some energy from the incident light.  The remaining light carries less energy, so it must be less bright.

5 0
4 years ago
1. When two atoms of the same nonmetal react, they often form a(an)
kkurt [141]

When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.

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3 years ago
A 6 ft tall person walks away from a 10 ft lamppost at a constant rate of 5 ft/s. What is the rate (in ft/s) that the tip of the
nalin [4]

Answer:

12.5 ft/s

Explanation:

Height of person = 6 ft

height of lamp post = 10 ft

According to the question,

dx / dt = 5 ft/s

Let the rate of tip of the shadow moves away is dy/dt.

According to the diagram

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Differentiate both sides with respect to t.

dy / dt = 2.5 dx / dt

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8 0
4 years ago
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