To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

Here,
k = Coulomb's constant
= Charge at each object
r = Distance between them
As the distance is doubled so,





Therefore the factor is 1/4
The gravitational force will be one quarter.
The gravitational force between two objects is given by the formula
F=GMm/r^2
here, r is the distance between the objects.
Thus the gravitational force is inversely proportional to the square of the distance between the objects, Therefore if the distance between two objects is doubled the force will be one quarter.
The electrical symbols are very important especially when fixing electrical appliances because it tells you where the wire of neutral and live go.
Impulse on the object: -20 kg m/s
Explanation:
The impulse exerted on an object is a vector quantity equal to the product between the force exerted on the object and the time interval during which the force is applied.
The impulse exerted on an object is also equal to its change in momentum. Mathematically,

where:
m is the mass of the object
u is the initial velocity
v is the final velocity
For the object in this problem, we have
m = 5 kg
u = +6 m/s
v = +2 m/s
Therefore, its impulse is:

The negative sign means the direction of the impulse is opposite to the direction of motion of the object.
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