I’m pretty sure it’s true x
Answer:
5.43 x 10^-3 Nm
Explanation:
N = 52.5, radius, r = 5.35 cm = 0.0535 m, B = 0.455 T, I = 25.3 mA = 0.0253 A
Torque = N I A B Sin theta
Here, theta = 90 degree
Torque = 52.5 x 0.0253 x 3.14 x 0.0535 x 0.0535 x 0.455
Torque = 5.43 x 10^-3 Nm
The rocket engine works on the basic principle proposed by Newton which is Newton’s Third Law.
1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

Rearranging the equation, we can write

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:
