Answer:
La masa de la mascota es de 11,24 kg.
Explanation:
Dado que la masa total de = 80 kg
Tenemos
Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N
La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona
Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3
La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota
1/2 × m × 6² = (80 - m) × 9.81 × 0.3
20943 · m = 235440
m = 235440/20943 = 11,24 kg
This is an elastic collision
bcuz i think they move apart after the collision
sorry if im wrong
m= 60g = 60/1000 Kg = 0.06 Kg
v = 2cm3 = 2 * (0.01^3) m3 = 2 *10^-6 m3
Density= m/v = 6 * 10^-2 / 2 *10^-6 = 3 *10^4 Kg/m3
There's no benefit from being stressed out, my lord.
x = 8 cos(3t + π/3)
When t=0, x = 8 cos(π/3)
Position = 8 cos(π/3) = 8 (0.5) = 4 .
Speed = first derivative of 8 cos(3t + π/3) =
- (8) (3) sin(3t + π/3) = - 24 sin(π/3) = -20.78
Acceleration = second derivative of 8 cos(3t + π/3)
= first derivative of - 24 sin(3t + π/3)
= - (24) (3) cos(3t + π/3)
= -72 cos(π/3) = -36 .
The period of the motion is the period of cos(3t + π/3) .
That's the same as the period of cos(3t) .
When is the first time after (3t=0) when (3t=2π) ? It's t = 2π/3 .
The period is 2π/3 .
The amplitude of the motion is the amplitude of 8 cos(.....) .
The amplitude of the cosine is 1 .
The amplitude of 8cos(...) is 8 .
Words cannot express my boundless gratitude
for the generous gift of your 5 points, my lord.
A full 1 point per answer !
The warm cloudy water and green bread-crust are delicious too.
There are none at all. A "light year" is a distance, not a time. It's the distance that light travels through vacuum in one year ... about 5.875 trillion miles.
