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galina1969 [7]
3 years ago
12

5 5/6 x negative 4/3

Mathematics
2 answers:
finlep [7]3 years ago
6 0
x= 5\frac{5}{6}*\frac{-4}{3}\\ x=\frac{35}{6}*\frac{-4}{3}\\ x=\frac{35*(-4)}{6*3}=\frac{-140}{18}=7\frac{7}{9}
vivado [14]3 years ago
5 0
Your answer is 7.77777777778
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Write a two-column proof. Given: <2 is congruent to <5; Segment AB is congruent to Segment DE Prove: Segment BC is congrue
kotykmax [81]

Answer:

proof

Step-by-step explanation:

Statements

Reasons

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

5 0
3 years ago
PLEASE HELP. I don't know what to do. I tryed all the equations and the problem but none matched up. plz help
xz_007 [3.2K]

Answer:

178

1900 = 5(x+202)

Step-by-step explanation:

Sasha= 5 times Bess and Jeremy

1900 = 5 (202 + X)

/5             /5

380 = 202 + x

-202     -202

178 = x


8 0
3 years ago
What is 9/20-3/20 in the simplest
stepan [7]
\frac{9}{20}- \frac{3}{20} =  \frac{6}{20}÷\frac{2}{2} = \frac{3}{10}
4 0
3 years ago
Read 2 more answers
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

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Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
4 years ago
7 1/4 % as a decimal
Mila [183]
7 1/4% equals 7.25% and there is your answer.
8 0
3 years ago
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