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4 years ago

BEST ANSWER GETS BRAINLIEST!!! PLEASE HELP

Mathematics

2 answers:

Flauer [41]4 years ago

8 0

2(4y + 1) as (4y + 1)(2)

u r just moving 2 here n there so this is commutative property multiplication

Jet001 [13]4 years ago

6 0

all you are doing is moving the 4 to another place in the equation by doing this you will not affect the answer at all
and thats distributive property!

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What is -2(x+1) simplified

IrinaVladis [17]

Answer:

-2x - 2

Step-by-step explanation:

-2(x + 1)

$(-2)(x+1)$
$(-2)(x)+(-2)(1)$
$-2x - 2$

Therefore, the answer is -2x - 2.

8 0

3 years ago

3. The perimeter of a square garden is 12 km. Find its area.

7nadin3 [17]

Answer:

the area of the garden is 9 square kilometers

Step-by-step explanation:

4s=12

s=3

A= 3*3 = 9

3 0

4 years ago

Read 2 more answers

a landscaper is designing a park in the shape of a kite with a fountain in the center, F. AK = 28 ft, PF=48 ft and F=32 ft. He w

Keith_Richards [23]

Answer:

169.9

Step-by-step explanation:

6 0

3 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

What is the value of z in the equation 2(4z − 3 − 21) = 166 − 46? 21 24 30 36

Nataly_w [17]

2(4z-3-21)=166-46

Combine like terms
2(4z-24)= 120

Distribute
8z-48= 120

Add 48 to both sides
8z= 168

Divide both sides by 8
z=21

Final answer: z=21

5 0

3 years ago

Read 2 more answers