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nika2105 [10]
3 years ago
10

Please help me with this Ixl answer

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0

D. The problem doesn’t state how many poppy seed muffins there are, so we can’t tell how many muffins are in the box. The fact that she buys the same box 2 days per week isn’t relevant.
elixir [45]3 years ago
3 0
D. I can't answer it without knowing how many poppy seed muffins are also in the Box
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Sandra has $20 in a savings account that earns 5% annually. The interest
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20*5%= 20* 0.05=1 , and 1 year= 365 days, so 1 *355=$355 in one year I think, but I’m not sure how to use the formula
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Is 4/10 more, less or equal to half​
zubka84 [21]

Answer:

less

Step-by-step explanation:

5/10 is equal to one half, but 4/10 is less than one half

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How to find the total surface area of a rectangular prism?
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If the length is taken as l , height is taken as h and breadth is taken as b . then

Area of the rectangular prism= 2( (l*b) + (b*h) + (h*l) ) 

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3 years ago
Can you help me with this
Jobisdone [24]

Answer:

HIEJFGUTHYBVFJKDLFKR

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Loggerhead turtles live and migrate around the Atlantic Ocean. Which of the following is an adaptation of Loggerhead turtles? *

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2 years ago
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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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