The answer is D:both A and B
Answer:
The correct answer is that the valuation would decrease total assets and stockholders’ equity by $101.00
Explanation:
Item Cost Market price Impact
Quantity
1 220 $ 4.40 $ 4.60 no impact as cost is lower
2 130 $ 6.20 $ 6.00 ($6.20-$6.00)*
130=$26
3 100 $ 10.00 $ 9.25 ($10-$9.25)*100 =$75
4 25 $ 20.50 $ 25.00 No impact as cost is lower
The total reduction in the value of inventory as a result of adopting the lower of cost or market price valuation is $101 ($75+$26),hence decreases total assets by $101 and the stockholders' equity(retained earnings which is a component of stockholders' equity ) by the same amount
Answer:
employed workers and persons who are officially unemployed
Explanation:
The labor force is the force that involves the labors who are employed and the unemployed i.e. officially
In an equation, it can be
Labor force = Employed workers + unemployed workers
It is a combination of both the employed and the unemployed workers
hence, the correct option is third
Therefore all the other options are wrong as they do not meet the criteria of the labor force
Answer:
high,high
not all prices adjust quickly
below
Explanation:
According to the sticky-wage theory, the economy is in a recession because the price level has declined so that real wages are too high, thus labor demand is too high.
Real wages decline as nominal wages are adjusted. As a result, the economy returns to full employment
According to the sticky-price theory, the economy is in a recession because not all prices adjust quickly.
As people observe the lower price level, the economy returns to the long-run aggregate supply curve.
According to the misperceptions theory, the economy is in a recession when the price level is below what was expected.
As people observe the lower price level, their expectations adjust.
Answer and Explanation:
The computation of composite score for each location is shown below:-
Composite score for A is
= 0.15 × 89 + .20 × 75 + 0.18 × 92 + 0.27 × 92 + 0.10 × 93 + 0.10 × 90
= 88.05
Composite score for B is
= 0.15 × 78 + .20 × 93 + 0.18 × 90 + 0.27 × 93 + 0.10 × 97 + 0.10 × 96
= 90.91
Composite score for C is
= 0.15 × 84 + .20 × 98 + 0.18 × 87 + 0.27 × 82 + 0.10 × 84 + 0.10 × 95
= 87.90
Therefore for computing the composite score for each location we simply multiply weight with A location and in the same manner of A, B and C
b. The maximum composite score from A, B and C is B