9514 1404 393
Answer:
- 340 quarters
- 1020 dimes
- 1031 nickels
- 2062 pennies
Step-by-step explanation:
x is the number of quarters
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a) d = 3x . . . . . . the number of dimes is 3 times the number of quarters
b) n = d + 11 = 3x +11 . . . . there are 11 more nickels than dimes
c) p = 2n = 2(3x +11) = 6x +22 . . . . there are twice as many pennies as nickels
d) The total number of coins is ...
x + d + n + p = 4453
x + (3x) +(3x +11) +(6x +22) = 4453
13x +33 = 4453
13x = 4420
x = 4420/13 = 340 . . . . number of quarters collected
3x = 1020 . . . . . . . . . . . .number of dimes collected
1020 +11 = 1031 . . . . . . . number of nickels collected
2·1031 = 2062 . . . . . . . . number of pennies collected
There were 340 quarters, 1020 dimes, 1031 nickels, and 2062 pennies collected.
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<em>Check</em>
340 +1020 +1031 +2062 = 4453 . . . as required
Answer:
(2 z + 3) (4 z^2 - 6 z + 9)
Step-by-step explanation:
8z3 + 27
a = 2z
b = 3
a^2 = (2z)^2 = 2z^2
ab = (2z)*3 =6z
b^2 = 3^2 =9
a3 + b3 = (a + b)(a2 – ab + b2)
8z^2 +27 = (2z+3) (4z^2 -6z +9)
It's an integer, and a real number
I think the answer is B. I hope I helped.