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Korolek [52]
3 years ago
10

What tools did the Greeks not use in the geometric constructions?

Mathematics
2 answers:
miskamm [114]3 years ago
6 0

A. Eraser
All the others were used though! Good luck!
Mnenie [13.5K]3 years ago
3 0

Options A and B are correct.

Eraser and Protractor were not used.

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HELPP!!! <br><br><br> What is the measure of ADC
Gwar [14]

72 degrees

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7 0
3 years ago
X + 34 = 40 what does "x" equal? explain
butalik [34]
Hey there!

6 + 34 = 40

so x = 6

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8 0
4 years ago
Read 2 more answers
Factor completely 2x2 − 2x − 40
Montano1993 [528]

Answer:

2(x-5)(x+4)

Step-by-step explanation:

2x^2 − 2x − 40

Factor out a 2

2(x^2 -x -20)

What 2 numbers multiply to -20 and add to -1

-5*4 = -20

-5+4 = -1

2(x-5)(x+4)

4 0
3 years ago
5a^5+60a^5-45a^4/15a^4
Artemon [7]
So basically, for this you would be combining like-terms and simplifying. This will give you -3a^8+65a^5
4 0
3 years ago
What is the surface area of the triangular prism shown?
Lunna [17]

Answer:

The first step that we are going to do is to solve the area of the top rectangle.  We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 15\ cm

Area = 375\ cm^2

The second side that we are going to solve for is the bottom rectangle.  We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 12\ cm

Area = 300\ cm^2

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 9\ cm

Area = 225\ cm^2

The final area that we have to determine are the side triangles.  After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles.  We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

Area = \frac{1}{2}* b*h

Area = \frac{1}{2}* 12\ cm*9\ cm

Area = 54\ cm^2

Multiply it by two to get the area for both of the triangles.

Area = 54\ cm^2 * 2

Area = 108\ cm^2

Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.

Area_{total}=375\ cm^2 + 300\ cm^2 + 225\ cm^2 + 108\ cm^2

Area_{total}=1008\ cm^2

Therefore, our final answer is option B, 1008 cm^2

Hope this helps!

4 0
2 years ago
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