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2 years ago

Find K' if the figure is reflected across the x-axis

Mathematics

1 answer:

snow_lady [41]2 years ago

5 0

<h3>Answer: K ' is at (1, 4)</h3>

Explanation:

Point K is located at (1, -4)

We use the rule that $(x,y) \to (x,-y)$ when reflecting over the x axis.

The x coordinate stays the same, but the y coordinate flips from positive to negative or vice versa.

Therefore, K(1,-4) will move to K ' (1, 4)

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Answer:

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Step-by-step explanation:

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astraxan [27]

ANSWER

The value of the expression is
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EXPLANATION

Method 1: Rewrite as product of
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The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
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${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

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Method 2: Use indices to solve.

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This implies that,

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3 years ago

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horsena [70]

Answer:

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