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Vadim26 [7]
3 years ago
14

Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0,

π] Find all values of x in the interval for which the function equals its average value. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer with Step-by-step explanation:

We are given that

f(x)=-sin x

[0,\infty]]

Average value of the function is given gy

f_{avg}=\frac{1}{b-a}\int_{a}^{b}f(x)dx=\frac{1}{\pi-0}\int_{0}^{\pi}-sinx dx

f_{avg}=\frac{1}{\pi}[cosx]^{\pi}_{0}

Using the formula

\int sin xdx=-cos x

f_{avg}=\frac{1}{\pi}(cos\pi-cos0)

f_{avg}=\frac{1}{\pi}(-1-1)=-\frac{2}{\pi}

f(x)=f_{avg}

-sinx=-\frac{2}{\pi}

sinx=\frac{2}{\pi}

x=sin^{-1}(\frac{2}{\pi})=0.69radian

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