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3 years ago

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Nicole is playing a video game where each round lasts \dfrac{7}{12} 12 7 start fraction, 7, divided by, 12, end fraction of an

hour. She has scheduled 3\dfrac343 4 3 3, start fraction, 3, divided by, 4, end fraction hours to play the game. How many rounds can Nicole play? rounds

2 answers:

dolphi86 [110]3 years ago

6 0

Answer:it is 45/7

Step-by-step explanation:

Harrizon [31]3 years ago

5 0

Total number of hours she schduled to play the game = 3 $\frac{3}{4}$ hours.

Let us convert mixed fraction into improper fraction

$3\frac{3}{4} = \frac{3*3+4}{4} = \frac{13}{4} \ hours.$

Duration of each round = $\frac{7}{12}$ .

In order to find the number of rounds Nicole can play, we need to divide total number of hours by duration of each round.

$\frac{13}{4}$ ÷ $\frac{7}{12}$

Converting division sign into multiplication flips the second fraction.

$=\frac{13}{4} \times \frac{12}{7}$

Crossing out 12 by 4, we get 3 on the top of second fraction.

$=\frac{13}{1} \times \frac{3}{7}$

$=\frac{39}{7} = 5.57...( Approximately).$

Because problem is about number of rounds.

So, total number of round would be 5.

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Here we're given
p=0.10 [ success = defective ]
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(b) x=2
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3 years ago

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NeX [460]

Answer:

Step-by-step explanation:

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To complete the square, we will do the first few steps all at once, since they are necessary but not complicated to follow all at once. Set the function equal to 0 first, then move the constant over to the other side:

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The most important rule for completing the square is that the leading coefficient (the number on the t-squared term) is a positive 1. Ours is, but if it wasn't it would need to be factored out.

Next, take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 to both sides:

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On the right is simple addition, but on the left side, during this process we created a perfect square binomial that will reflect the h coordinate of the vertex. We will state that binomial and do the addition on the right both at the same time:

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If you FOIL out the (t + 3)(t + 3) you will get back the polynomial $t^2+6t+9$

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