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algol [13]
3 years ago
6

Given the function f(x) = log2(x + 6), find the value of f−1(3).

Mathematics
2 answers:
Svetlanka [38]3 years ago
8 0

Answer:

f^{-1}(3)=2 is correct

Step-by-step explanation:

Given the function f(x) = \log_2(x + 6)

We need to find f^{-1}(3)

First we find the inverse of the function

y= \log_2(x + 6)

Switch x and y

x= \log_2(y + 6)

Solve for y

2^x=y + 6

y=2^x-6

\therefore, f^{-1}(x)=2^x-6

Put x=3

f^{-1}(3)=2^3-6\Rightarrow 8-6=2

Thus, f^{-1}(3)=2 is correct

Lina20 [59]3 years ago
5 0
The first answer choice is your answer :)
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riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

P(Z>1.1547)=1-0.8789

P(Z>1.1547)=0.1241

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

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3 years ago
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nirvana33 [79]
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