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Dominik [7]
2 years ago
6

Find the equation of the tangent to the circle x2 + y2 = 109 at point (-10,3)

Mathematics
1 answer:
konstantin123 [22]2 years ago
4 0

Answer:

10x - 3y = -109 .

Step-by-step explanation:

x^2 + y^2 = 109

Implicit Differentiation:

2x + 2y.y' = 0

y' = -2x/2y = -x/y

So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.

Equation of the tangent:

y - y1 = m(x - x1)

y - 3 = 10/3(x + 10)

y - 3 = 10/3 x + 100/3

3y - 9 = 10x + 100

-109 + 3y = 10x

10x - 3y = -109  

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Answer:

24

Step-by-step explanation:

I think you ask about LCM

6- 2×3

8- 2×2×2

lcm = 2×2×2×3 = 24

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3 years ago
Please help asap! Will give brainliest! Please answer correctly!<br> No guessing!
Greeley [361]

Answer:

Option B

Step-by-step explanation:

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5 0
3 years ago
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How do you solve for 5/6w = 2/3 (the answer is w= 4/5) I just don’t know how to show it.
Readme [11.4K]

Answer:

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How to subrtact a negative from a negative?
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ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of -8x^2y^3 \div xy.

-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}

                    =\frac{-8\times x\times x\times y\times y\times y}{xy}

Taking common term xy outside in the numerator.

                    =\frac{xy(-8\times x\times y\times y)}{xy}

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Thus, the quotient of -8x^2y^3 \div xy is -8xy^2.

Given the quotient of -8x^2y^3 \div xy is same as the product  of 4xy and ____.

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Divide both sides by 4xy, we get

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Cancel the common terms in both numerator and denominator.

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Hence the missing term of the product is –2xy.

4 0
3 years ago
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