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Zolol [24]
3 years ago
9

The graph of the quadratic function shown on the left is

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answers -3 and 4. -3 and 4

Step-by-step explanation:

balandron [24]3 years ago
7 0

Answer:

  • For the <u>Y=</u> it is <u>-3 and 4</u>
  • For the <u>0=</u> it is also <u>-3 and 4 </u>

Step-by-step explanation:

  • These are the correct answers because when finding the solutions to an equation in Vertex Form, you take both of the X values and switch their signs to get the answer. This is proven to be right because they were the right answers on ED.
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3 0
3 years ago
One solution to a quadratic function, h, is given.
Margaret [11]

Answer:

B. The other solution to function h is -4-i\,7.

Step-by-step explanation:

From Algebra, we remember that quadratic functions of the form a\cdot x^{2}+b\cdot x + c has solutions of the form:

x = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}, where both are complex if and only if \sqrt{b^{2}-4\cdot a \cdot c}< 0.

Hence, if one solution of the quadratic function is -4+i\,7, then the other solution is -4-i\,7. The correct answer is B.

7 0
3 years ago
6x + 5y = 16<br> −6x + 7y = 80
Kobotan [32]

The equation of the line in point-slope form is equal to

The equation of the line in standard form is equal to

step 1

Find the slope m

Let

step 2

convert to standard form

6 0
3 years ago
Solve the equation by the Quadratic Formula. Round to the nearest tenth, if necessary. Write your solutions from least to greate
Marat540 [252]

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = 10, b = -19 and c = 6.

Next step is to plug in these values in the above formula. Therefore,

So,

So,

Hope this helps you!

3 0
2 years ago
When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom
gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x +  8

Expand the equation

x^2 + 6x +  8 = x^2 + 4x + 2x +  8

Factorize the equation

x^2 + 6x +  8 = (x + 2)(x + 4)


Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0
1 year ago
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