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4 years ago

The graph of the quadratic function shown on the left is

Mathematics

2 answers:

Ray Of Light [21]4 years ago

7 0

Answers -3 and 4. -3 and 4

Step-by-step explanation:

balandron [24]4 years ago

7 0

Answer:

For the Y= it is -3 and 4

For the 0= it is also -3 and 4

Step-by-step explanation:

These are the correct answers because when finding the solutions to an equation in Vertex Form, you take both of the X values and switch their signs to get the answer. This is proven to be right because they were the right answers on ED.

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If g(x) = x - 3 and f(x) = 3 - x2; find f(g(-2))=

const2013 [10]

Answer:

Step-by-step explanation:

g(-2) = -2 -3 = -5

f(-5)= 3 - (-5)^2 = 3 - 25 = -22

5 0

4 years ago

Evaluate: -8 over 9 + 4 over 9 - 2 over 9

stepan [7]

The answer is -2/3 from the solution above

4 0

3 years ago

Read 2 more answers

What is the slope-intercept equation of the line below?

Andru [333]

Answer:

y= -3x+4

I hope this helps <3 have an amazing and wonderful day <3

Step-by-step explanation:

3 0

3 years ago

HELP PLEASE ANSWER QUICK VERY EASY!!!

sleet_krkn [62]

Answer:

id say c. because its the closest number that corresponds with the graph.

5 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago