Answer:
64
Step-by-step explanation:
the answer is 64 hope this helps
Answer:
80 possible combinations
Step-by-step explanation:
each crust can have a choice of 2 different types of meat and 4 different types of vegetables
if crust1 has four different meat options and two types of meat on each pizza then there are six options possible for the meat on each crust. Now you have 8 veggies and each pizza can have 4 veggies. then there are 56 different veggie combinations.(4+6+56)= 80
Answer:
He needs $15 more
Step-by-step explanation:
since each ticket costs $10 dollars, and there is 6 tickets, we need to multiply 10 x 6 to get the total cost of all tickets
10 x 6 = $60
To find how much more money he needs to buy all tickets, we need to subtract $45 from the total cost of tickets, which is $60
$60 - $45 = $15
Hope you understand this explanation!
It's essential that you use " ^ " to indicate exponentiation if you want to communicate your ideas here accurately.
<span>x2e5x + 3xe5x − e5x = 0 should be written as
x^2e^(5x) + 3xe^(5x) - 1e^(5x) = 0.
e^(5x) can be factored out of all four terms, leaving us with
e^(5x) [x^2 + 3x - 1] = 0. e^(5x) is never zero, so no solution there.
However, we can set x^2 + 3x - 1 equal to zero and solve for x:
-3 plus or minus sqrt(3^2 - 4(1)(-1) )
x = ----------------------------------------------------
2
-3 plus or minus sqrt(13)
= ----------------------------------------
2
So the original equation has two roots.</span>
