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3 years ago

WILL GIVE BRAINLIST AND 21 POINTS

Mathematics

2 answers:

sweet [91]3 years ago

8 0

Answer:

1) 4/(6+4+5) = 4/15

2) incomplete data

3) 16/(12+14+16+18) = 16/60 = 4/15

= 27%

4) (1+3)/10= 4/10 = 2/5

5) 12/30 = 0.4 = 40%

zvonat [6]3 years ago

8 0

Answer:

All of those answers are correct except number 2 that one is 0.3

Step-by-step explanation:

1.) 4/15

2.) 0.3

3.) 27%

4.) 2/5

5.) 40%

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A box is filled with candies in different colors. There are 40 white candies, 24 green ones, 24 yellow ones, 12 red ones, and 20

AleksAgata [21]

Answer:

3/10 or 30% chance red and green being pulled

Step-by-step explanation:

to get your fraction you do your amount wanted pulled (red and green) over the amount total (all of the colors)

24 + 12 = 36

40 + 24 + 12 + 24 + 20 = 120

36/120 now reduce 6

6/20 reduce by 2

3/10

5 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

AB and BC are tangent to circle D. Find x if AB = 2x + 9 and BC = 3x + 6. Find x.

mestny [16]

It woulds be x+15 because if you take 2x and subtracted from the 3x then you get x and then you add the 9 and 6 witch you get 15

6 0

3 years ago

Read 2 more answers

I need helpabdjbajdbajdb

gizmo_the_mogwai [7]

Answer:

c=10